minimize  x^T Q x + c^T x + C
s.t.      Gx <= h
Ax == b
lb <= x <= ub
x_i is integer or continuous variablce

This optimization problem is called Quadratic Programming (QP) Problem. For example, the following problem is one of the QP.

from flopt import Variable, Problem

# Variables
a = Variable('a', lowBound=0, upBound=1, cat='Integer')
b = Variable('b', lowBound=1, upBound=2, cat='Continuous')
c = Variable('c', lowBound=1, upBound=3, cat='Continuous')

# Problem
prob = Problem()
prob += a*a + a*b + b + c + 2
prob += a + b <= 2
prob += b - c == 3

prob.show()
>>> Name: None
>>>   Type         : Problem
>>>   sense        : minimize
>>>   objective    : a*a+(a*b)+b+c+2
>>>   #constraints : 2
>>>   #variables   : 3 (Continuous 2, Integer 1)
>>>
>>>   C 0, name None, a+b-2 <= 0
>>>   C 1, name None, b-c-3 == 0

## flopt to QP

We convert problem modeled in flopt into QP form as follows.

from flopt.convert import QpStructure
qp = QpStructure.fromFlopt(prob)

To show the contents of qp, use .show() method. In addition, we can access each element using attributes of QpStructure, for example, qp.Q.

print(qp.show())
>>> QpStructure
>>> obj  1/2 x.T.dot(Q).dot(x) + c.T.dot(x) + C
>>> s.t. Gx <= h
>>>      Ax == b
>>>      lb <= x <= ub
>>>
>>> #x
>>> 3
>>>
>>> Q
>>> [[0. 0. 0.]
>>>  [0. 0. 1.]
>>>  [0. 1. 2.]]
>>>
>>> c
>>> [1. 1. 0.]
>>>
>>> C
>>> 2
>>>
>>> G
>>> [[0. 1. 1.]]
>>>
>>> h
>>> [2.]
>>>
>>> A
>>> [[-1.  1.  0.]]
>>>
>>> b
>>> [3.]
>>>
>>> lb
>>> [1. 1. 0.]
>>>
>>> ub
>>> [3. 2. 1.]
>>>
>>> x
>>> [Variable("c", 1, 3, "Continuous", 2.0)
>>>  Variable("b", 1, 2, "Continuous", 1.5) Variable("a", 0, 1, "Integer", 0)]

### Formulation with only equal constraints

You can obtain the formulaton with only eqaual constraints by .toAllEq()

minimize  c^T x + C
s.t.      Ax == b
lb <= x <= ub
x_i is integer or continuous variablce
qp.toAllEq()

### Formulation with only non-equal constraints

You can obtain the formulaton with only non-eqaual constraints by .toAllNeq()

minimize  c^T x + C
s.t.      Gx <= h
lb <= x <= ub
x_i is integer or continuous variablce
qp.toAllNeq()

## QP to flopt

# make QP model
Q = [[1, 2, 0],
[2, 2, 1],
[0, 1, 0]]
c = [1, 1, 1]
C = 2
A = [[1, 0, 1],
[1, -1, 0]]
b = [2, 3]
lb = [1, 1, 0]
ub = [2, 3, 1]
types='Continuous'

from flopt.convert import QpStructure
prob = QpStructure(Q, c, C, A=A, b=b, lb=lb, ub=ub, types=types).toFlopt()

prob.show()
>>> Name: None
>>>   Type         : Problem
>>>   sense        : minimize
>>>   objective    : 0.5*(x_0^2)+(2.0*(x_0*x_1))+x_0+(x_1^2)+(x_1*x_2)+x_1+x_2+2
>>>   #constraints : 2
>>>   #variables   : 3 (Continuous 3)
>>>
>>>   C 0, name None, x_0+x_2-2.0 == 0
>>>   C 1, name None, x_0-x_1-3.0 == 0